QUESTIONS
Question 1
Identify the scatter plot that has one or more outliers. Select all that apply.
[Graphs]
Question 2
Suppose you computed r=0.142 using n=82 data points. Using the critical values table below, determine if the value of r is significant or not.
| df | CV (+ and -) | df | CV (+ and -) | df | CV (+ and -) | df | CV (+ and -) |
| 1 | 0.997 | 11 | 0.555 | 21 | 0.413 | 40 | 0.304 |
| 2 | 0.950 | 12 | 0.532 | 22 | 0.404 | 50 | 0.273 |
| 3 | 0.878 | 13 | 0.514 | 23 | 0.396 | 60 | 0.250 |
| 4 | 0.811 | 14 | 0.497 | 24 | 0.388 | 70 | 0.232 |
| 5 | 0.754 | 15 | 0.482 | 25 | 0.381 | 80 | 0.217 |
| 6 | 0.707 | 16 | 0.468 | 26 | 0.374 | 90 | 0.205 |
| 7 | 0.666 | 17 | 0.456 | 27 | 0.367 | 100 | 0.195 |
| 8 | 0.632 | 18 | 0.444 | 28 | 0.361 | ||
| 9 | 0.602 | 19 | 0.433 | 29 | 0.355 | ||
| 10 | 0.576 | 20 | 0.423 | 30 | 0.349 |
- r is significant because it is between the positive and negative critical values.
- r is not significant because it is between the positive and negative critical values.
- r is significant because it is not between the positive and negative critical values.
- r is not significant because it is not between the positive and negative critical values.
Question 3
The table shows data collected on the relationship between the average daily temperature and time spent watching television. The line of best fit for the data is yˆ=−0.66x+88.5.
| Temperature (Degrees) | Minutes Watching Television |
| 35 | 66 |
| 45 | 58 |
| 55 | 52 |
| 65 | 46 |
Temperature (Degrees) 35455565 Minutes Watching Television 66585246
(a) According to the line of best fit, the predicted number of minutes spent watching television for an average daily temperature of 46 degrees is 58.14.
(b) Is it reasonable to use this line of best fit to make the above prediction?
- The estimate, a predicted time of 14minutes, is both unreliable and unreasonable.
- The estimate, a predicted time of 14minutes, is reliable but unreasonable.
- The estimate, a predicted time of 14minutes, is unreliable but reasonable.
- The estimate, a predicted time of 14minutes, is both reliable and reasonable.
Question 4
The table shows data collected on the relationship between the average daily temperature and time spent watching television. The line of best fit for the data is yˆ=−0.66x+88.5. Assume the line of best fit is significant and there is a strong linear relationship between the variables.
| Temperatures (Degrees) | Minutes Watching Television |
| 35 | 66 |
| 45 | 58 |
| 55 | 52 |
| 65 | 46 |
(a) According to the line of best fit, what would be the predicted number of minutes spent watching television for an average daily temperature of 46 degrees? Round your answer to two decimal places, as needed.
Question 5
Given that n=82 data points are collecting when studying the relationship between average daily temperature and time spent watching television, use the critical values table below to determine if a calculated value of r=−0.974 is significant or not.
| df | CV (+ and -) | df | CV (+ and -) | df | CV (+ and -) | df | CV (+ and -) |
| 1 | 0.997 | 11 | 0.555 | 21 | 0.413 | 40 | 0.304 |
| 2 | 0.950 | 12 | 0.532 | 22 | 0.404 | 50 | 0.273 |
| 3 | 0.878 | 13 | 0.514 | 23 | 0.396 | 60 | 0.250 |
| 4 | 0.811 | 14 | 0.497 | 24 | 0.388 | 70 | 0.232 |
| 5 | 0.754 | 15 | 0.482 | 25 | 0.381 | 80 | 0.217 |
| 6 | 0.707 | 16 | 0.468 | 26 | 0.374 | 90 | 0.205 |
| 7 | 0.666 | 17 | 0.456 | 27 | 0.367 | 100 | 0.195 |
| 8 | 0.632 | 18 | 0.444 | 28 | 0.361 | ||
| 9 | 0.602 | 19 | 0.433 | 29 | 0.355 | ||
| 10 | 0.576 | 20 | 0.423 | 30 | 0.349 |
- r is significant because it is between the positive and negative critical values.
- r is not significant because it is between the positive and negative critical values.
- r is significant because it is not between the positive and negative critical values.
- r is not significant because it is not between the positive and negative critical values.
Question 6
Which of the following points is most likely an outlier in the scatter plot above? Select all that apply.
- (0, 29)
- (5, 329)
- (0, 18)
- (0, 462)
Question 7
Of the scatter plots below, which has one or more outliers?
[Graphs]
Question 8
Determine which of the following scatter plots has one or more outliers. Select all that apply.
[Graphs]
Question 9
Suppose you computed r=0.659 using n=32 data points. Using the critical values table below, determine if the value of r is significant or not.
| df | CV (+ and -) | df | CV (+ and -) | df | CV (+ and -) | df | CV (+ and -) |
| 1 | 0.997 | 11 | 0.555 | 21 | 0.413 | 40 | 0.304 |
| 2 | 0.950 | 12 | 0.532 | 22 | 0.404 | 50 | 0.273 |
| 3 | 0.878 | 13 | 0.514 | 23 | 0.396 | 60 | 0.250 |
| 4 | 0.811 | 14 | 0.497 | 24 | 0.388 | 70 | 0.232 |
| 5 | 0.754 | 15 | 0.482 | 25 | 0.381 | 80 | 0.217 |
| 6 | 0.707 | 16 | 0.468 | 26 | 0.374 | 90 | 0.205 |
| 7 | 0.666 | 17 | 0.456 | 27 | 0.367 | 100 | 0.195 |
| 8 | 0.632 | 18 | 0.444 | 28 | 0.361 | ||
| 9 | 0.602 | 19 | 0.433 | 29 | 0.355 | ||
| 10 | 0.576 | 20 | 0.423 | 30 | 0.349 |
- r is significant because it is between the positive and negative critical values.
- r is not significant because it is between the positive and negative critical values.
- r is significant because it is not between the positive and negative critical values.
- r is not significant because it is not between the positive and negative critical values.
Question 10
Given that n=23 data points are collecting when studying the relationship between average daily temperature and time spent sleeping, use the critical values table below to determine if a calculated value of r=−0.256 is significant or not.
| df | CV (+ and -) | df | CV (+ and -) | df | CV (+ and -) | df | CV (+ and -) |
| 1 | 0.997 | 11 | 0.555 | 21 | 0.413 | 40 | 0.304 |
| 2 | 0.950 | 12 | 0.532 | 22 | 0.404 | 50 | 0.273 |
| 3 | 0.878 | 13 | 0.514 | 23 | 0.396 | 60 | 0.250 |
| 4 | 0.811 | 14 | 0.497 | 24 | 0.388 | 70 | 0.232 |
| 5 | 0.754 | 15 | 0.482 | 25 | 0.381 | 80 | 0.217 |
| 6 | 0.707 | 16 | 0.468 | 26 | 0.374 | 90 | 0.205 |
| 7 | 0.666 | 17 | 0.456 | 27 | 0.367 | 100 | 0.195 |
| 8 | 0.632 | 18 | 0.444 | 28 | 0.361 | ||
| 9 | 0.602 | 19 | 0.433 | 29 | 0.355 | ||
| 10 | 0.576 | 20 | 0.423 | 30 | 0.349 |
- r is significant because it is between the positive and negative critical values.
- r is not significant because it is between the positive and negative critical values.
- r is significant because it is not between the positive and negative critical values.
- r is not significant because it is not between the positive and negative critical values.
Question 11
The table shows data collected on the relationship between time spent playing video games and time spent with family. The line of best fit for the data is yˆ=−0.36x+94.5.
| Video Games (Minutes) | Time with Family (Minutes) |
| 40 | 80 |
| 55 | 75 |
| 70 | 69 |
| 85 | 64 |
(a) According to the line of best fit, the predicted number of minutes spent with family for someone who spent 36 minutes playing video games is 81.54.
(b) Is it reasonable to use this line of best fit to make the above prediction?
- The estimate, a predicted time of 54minutes, is reliable but unreasonable.
- The estimate, a predicted time of 54minutes, is unreliable but reasonable.
- The estimate, a predicted time of 54minutes, is both unreliable and unreasonable.
- The estimate, a predicted time of 54minutes, is both reliable and reasonable.
Question 12
The table shows data collected on the relationship between time spent playing video games and time spent with family. The line of best fit for the data is yˆ=−0.36x+94.5.
Assume the line of best fit is significant and there is a strong linear relationship between the variables.
| Video Games (Minutes) | Time with Family (Minutes) |
| 40 | 80 |
| 55 | 75 |
| 70 | 69 |
| 85 | 64 |
(a) According to the line of best fit, what would be the predicted number of minutes spent with family for someone who spent 36 minutes playing video games? Round your answer to two decimal places.
ANSWERS:
Question 1
Identify the scatter plot that has one or more outliers. Select all that apply.
[Graphs]
Answer
[Graph]
Question 2
Suppose you computed r=0.142 using n=82 data points. Using the critical values table below, determine if the value of r is significant or not.
| df | CV (+ and -) | df | CV (+ and -) | df | CV (+ and -) | df | CV (+ and -) |
| 1 | 0.997 | 11 | 0.555 | 21 | 0.413 | 40 | 0.304 |
| 2 | 0.950 | 12 | 0.532 | 22 | 0.404 | 50 | 0.273 |
| 3 | 0.878 | 13 | 0.514 | 23 | 0.396 | 60 | 0.250 |
| 4 | 0.811 | 14 | 0.497 | 24 | 0.388 | 70 | 0.232 |
| 5 | 0.754 | 15 | 0.482 | 25 | 0.381 | 80 | 0.217 |
| 6 | 0.707 | 16 | 0.468 | 26 | 0.374 | 90 | 0.205 |
| 7 | 0.666 | 17 | 0.456 | 27 | 0.367 | 100 | 0.195 |
| 8 | 0.632 | 18 | 0.444 | 28 | 0.361 | ||
| 9 | 0.602 | 19 | 0.433 | 29 | 0.355 | ||
| 10 | 0.576 | 20 | 0.423 | 30 | 0.349 |
- r is significant because it is between the positive and negative critical values.
- r is not significant because it is between the positive and negative critical values.
- r is significant because it is not between the positive and negative critical values.
- r is not significant because it is not between the positive and negative critical values.
Answer
r is not significant because it is between the positive and negative critical values.
Question 3
The table shows data collected on the relationship between the average daily temperature and time spent watching television. The line of best fit for the data is yˆ=−0.66x+88.5.
| Temperature (Degrees) | Minutes Watching Television |
| 35 | 66 |
| 45 | 58 |
| 55 | 52 |
| 65 | 46 |
Temperature (Degrees) 35455565 Minutes Watching Television 66585246
(a) According to the line of best fit, the predicted number of minutes spent watching television for an average daily temperature of 46 degrees is 58.14.
(b) Is it reasonable to use this line of best fit to make the above prediction?
- The estimate, a predicted time of 14minutes, is both unreliable and unreasonable.
- The estimate, a predicted time of 14minutes, is reliable but unreasonable.
- The estimate, a predicted time of 14minutes, is unreliable but reasonable.
- The estimate, a predicted time of 14minutes, is both reliable and reasonable.
Answer
The estimate, a predicted time of 58.14 minutes, is both reliable and reasonable.
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